375x^2-4500x+1200=0

Solution for 375x^2-4500x+1200=0 equation:

375x^2-4500x+1200=0

a = 375; b = -4500; c = +1200;
Δ = b2-4ac
Δ = -45002-4·375·1200
Δ = 18450000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18450000}=\sqrt{90000*205}=\sqrt{90000}*\sqrt{205}=300\sqrt{205}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4500)-300\sqrt{205}}{2*375}=\frac{4500-300\sqrt{205}}{750}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4500)+300\sqrt{205}}{2*375}=\frac{4500+300\sqrt{205}}{750}
$